Directions: (26-30) |
Gauss' Low and Its Significance |
Gauss's law and Coulomb's law, although expressed in different forms, are equivalent ways of describing the relation between charge and electric field in static conditions. Gauss's law is \[{{\varepsilon }_{0}}\phi ={{q}_{encl}}\] when \[{{q}_{encl}}\] is the net charge inside an imaginary closed surface called Gaussian surface, \[\phi =\oint\limits_{{}}{\overrightarrow {E}}\,.\,d\overrightarrow{A}\] gives the electric flux through the Gaussian surface. The two equations hold only when the net charge is in vaccum or air. |
A) \[\oint{\overrightarrow{E}}\,.\,d\,\overrightarrow{s}\ne \]on any surface
B) \[\oint{\overrightarrow{E}}\,.\,d\,\overrightarrow{s}\]could not be defined
C) \[\oint{\overrightarrow{E}}\,.\,d\,\overrightarrow{s}=\infty \]if charge is inside
D) \[\oint{\overrightarrow{E}}\,.\,d\,\overrightarrow{s}=0\] if charge is outside, \[\oint{\overrightarrow{E}}\,.\,d\,\overrightarrow{s}=\frac{q}{{{\varepsilon }_{0}}}\]if charge is inside.
Correct Answer: D
Solution :
If there is only one type of charge in the universe then it will produce electric field somehow. Hence Gauss's law is valid.You need to login to perform this action.
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