Direction Q.11 to 15 |
Coulomb's law states that the electrostatic force of attraction or repulsion acting between two stationary points charges is given by |
\[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] |
where F denotes the force between two charges \[{{q}_{1}}\]and \[{{q}_{2}}\] separated by a distance r in free space, e q is a constant known as permittivity of free space. Free space is vacuum and may be taken to be air practically. |
If free space is replaced by a medium, then E o is replaced by \[\left( {{\varepsilon }_{0}}k \right)\]or \[\left( {{\varepsilon }_{0}}{{\varepsilon }_{r}} \right)\]where k is known as dielectric constant or relative permittivity. |
Read the above passage carefully and give the answer of the following questions. |
A) Electrostatic force acting between the two charges
B) Nature of the medium between the two charges
C) Magnitude of the two charges
D) Distance between the two charges
Correct Answer: B
Solution :
(b) Nature of the medium between the two charges The proportionality constant k depends on the nature of the medium between the two charges.You need to login to perform this action.
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