A) \[17\times {{10}^{-22}}\,N/C\]
B) \[1\centerdot 5\times {{10}^{-15}}\,N/C\]
C) \[1\centerdot 9\times {{10}^{-10}}\,N/C\]
D) zero
Correct Answer: C
Solution :
In region II or between the plates, the electric field \[{{E}_{II}}={{E}_{A}}-{{E}_{B}}=\frac{\sigma }{2{{\varepsilon }_{0}}}+\frac{\sigma }{2{{\varepsilon }_{0}}}\] \[=\frac{\sigma \left( {{\sigma }_{A}}\,or\,{{\sigma }_{B}} \right)}{{{\varepsilon }_{0}}}=\frac{17\,.\,0\times {{10}^{-22}}}{8\,.\,85\times {{10}^{-12}}}\] \[E=1\,.\,9\times {{10}^{-10}}N\,{{C}^{-1}}\].
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