A) \[5\centerdot 6\times {{10}^{-18}}C\]
B) \[3\centerdot 2\times {{10}^{-18}}C\]
C) \[4\centerdot 5\times {{10}^{-19}}C\]
D) \[8\centerdot 6\times {{10}^{-19}}C.\]
Correct Answer: B
Solution :
From, \[q=ne,\]\[n=\frac{q}{e}=\frac{3\,.\,2\times {{10}^{-18}}}{1\,.\,6\times {{10}^{-19}}}=20\] As n is an integer, hence this value of charge is possible.
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