A) \[6\centerdot 25\times {{10}^{27}}\]
B) \[6\centerdot 25\times {{10}^{19}}\]
C) \[6\centerdot 25\times {{10}^{28}}\]
D) \[6\centerdot 25\times {{10}^{9}}\]
Correct Answer: D
Solution :
Charge on the body is q = ne \[\therefore \]No. of electrons present on the body is \[n=\frac{q}{e}=\frac{1\times {{10}^{-9}}C}{1\,.\,6\times {{10}^{-19}}C}\] \[=6\,.\,25\times {{10}^{9}}.\]
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