A) 190.19 years
B) 150.12 years
C) 198.19 years
D) 188.21 years
Correct Answer: C
Solution :
Here, \[n={{10}^{9}}\]electrons per second Charge given per second, \[q=ne={{10}^{9}}\times 1\,.\,6\times {{10}^{-19}}C\] \[q=1\,.\,6\times {{10}^{-10}}C\] Total charge, Q = 1 C(given) \[\therefore \]Time required \[=\frac{Q}{q}=\frac{1}{1.6\times {{10}^{-10}}}s\] \[=6\,.\,25\times {{10}^{9}}\,s\] \[\therefore \,\,\,\frac{6.\,25\times {{10}^{9}}}{3600\times 24\times 365}year=198\,.\,19\,years\]
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