A) \[3\times {{10}^{3}}V\]
B) \[6\times {{10}^{4}}V\]
C) \[-9\times {{10}^{3}}V\]
D) \[-3\times {{10}^{3}}V\]
Correct Answer: C
Solution :
Here, \[q=2\,\mu C=2\times {{10}^{-6}}C\], \[{{r}_{A}}=2\,m\], \[{{r}_{B}}=1\,m\] \[\therefore \,\,{{V}_{A}}-{{V}_{B}}=\frac{q}{4\pi {{\varepsilon }_{0}}}\left[ \frac{1}{{{r}_{A}}}-\frac{1}{{{r}_{B}}} \right]\] \[=2\times {{10}^{-6}}\times 9\times {{10}^{9}}\left[ \frac{1}{2}-\frac{1}{1} \right]V\] \[=-9\,\times {{10}^{3}}\,V\]
You need to login to perform this action.
You will be redirected in
3 sec
