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12th Class Physics Electrostatics & Capacitance Question Bank Case Based (MCQs) - Electric Potential and Capacitance

  • question_answer
    If a charge of \[+2\centerdot 0\times {{10}^{-8}}\] is placed on the positive plate and a charge of \[-1\centerdot 0\times {{10}^{-8}}C\] on the negative plate of a parallel plate capacitor of capacitance \[1\centerdot 2\times {{10}^{-3}}\mu F\], then the potential difference developed between the plates is

    A) \[6\centerdot 25V\]

    B) \[3\centerdot 0V\]

    C) \[12\centerdot 5V\]

    D) 25V

    Correct Answer: C

    Solution :

    Here, \[V=\frac{{{q}_{1}}-{{q}_{2}}}{2C}\] \[=\frac{2\,.\,0\times {{10}^{-8}}+1\,.\,0\times {{10}^{-8}}}{2\times 1\,.\,2\times {{10}^{-9}}}\] \[=12.\,5\,V\]


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