A) \[6\centerdot 25V\]
B) \[3\centerdot 0V\]
C) \[12\centerdot 5V\]
D) 25V
Correct Answer: C
Solution :
Here, \[V=\frac{{{q}_{1}}-{{q}_{2}}}{2C}\] \[=\frac{2\,.\,0\times {{10}^{-8}}+1\,.\,0\times {{10}^{-8}}}{2\times 1\,.\,2\times {{10}^{-9}}}\] \[=12.\,5\,V\]You need to login to perform this action.
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