A) 1.5 volts
B) 2 volts
C) 0.5 volts
D) 1 volt
Correct Answer: D
Solution :
(d) 1 volt Emf induced, \[\varepsilon =Blv\] Here, \[\overrightarrow{B},\,\,\overrightarrow{l}\]and \[\overrightarrow{v}\] are mutually perpendicular For given B and \[l,\,\,\varepsilon \propto v\]. \[\therefore \frac{{{\varepsilon }_{1}}}{{{\varepsilon }_{2}}}=\frac{{{v}_{1}}}{{{v}_{2}}}\] Here, \[{{\varepsilon }_{1}}=15\,V,{{v}_{1}}=15\,\,km/hr=15\times \frac{5}{18}m{{s}^{-1}}\] \[{{v}_{2}}=10\,km/hr=10\times \frac{5}{18}m{{s}^{-1}},{{\varepsilon }_{2}}=?\] So, \[\frac{1.5}{{{\varepsilon }_{2}}}=\frac{15\times \frac{5}{18}}{10\times \frac{5}{18}}=\frac{3}{2};{{\varepsilon }_{2}}=1V\]
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