A) weber ampere
B) weber\[^{-1}\] ampere
C) ohm second
D) farad
Correct Answer: C
Solution :
The magnitude of induced emf is \[\left| \varepsilon \right|=L\frac{dI}{dt}\Rightarrow L=\frac{\left| \varepsilon\right|\,dt}{dI}\] Or \[L=\frac{volt\times \sec ond}{ampere}=ohm\,\sec ond\]
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