A) 200 V
B) 250 V
C) 300 V
D) 350 V
Correct Answer: B
Solution :
(b) 250 V Here \[L=10\] henry, \[{{l}_{1}}=9A,{{l}_{2}}=4A\] and \[\Delta t=0.2\] second Then induced e.m.f. \[{{\varepsilon }_{1}}=-L\frac{dl}{dt}=-L\frac{({{l}_{2}}-{{l}_{1}})}{\Delta t}\] \[=\frac{-10\times (4-9)}{0.2}=\frac{50}{0.2}=250V\]You need to login to perform this action.
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