A) \[1\centerdot 5\,Volts\]
B) 2 volts
C) \[0\centerdot 5\,Volts\]
D) 1 volt
Correct Answer: D
Solution :
Emf induced, \[\varepsilon =B/v\] Here, \[\overrightarrow{B}\], \[\overrightarrow{l}\]and \[\overrightarrow{v}\] are mutually pependicular For given B and l, \[\varepsilon \propto v\]. \[\therefore \,\,\,\,\,\,\,\,\,\frac{{{\varepsilon }_{1}}}{{{\varepsilon }_{2}}}=\frac{{{v}_{1}}}{{{v}_{2}}}\] Here, \[{{\varepsilon }_{1}}=\,1\,.\,5\,V\], \[{{v}_{1}}=15\,\,km/hr\] \[=15\times \frac{5}{18}\,m\,{{s}^{-1}}\] \[{{v}_{2}}=10\,km/hr=10\times \frac{5}{18}m{{s}^{-1}},\,{{\varepsilon }_{2}}=?\]
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