A) 0.5 Wb
B) 12.5 Wb
C) zero
D) 2 Wb
Correct Answer: B
Solution :
(b) 12.5 Wb Here, \[l=2.5A,\,\,L=5H\] Magnetic flux linked with the coil is \[{{\phi }_{B}}=Ll(5H)(2.5\,A)=12.5\,Wb\]
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