| Direction: Q.11 to Q.15 |
| This energy possessed by a system of charges by virtue of their positions. When two like charges lie infinite distance apart, their potential energy is zero because no work has to be done in moving one charge at infinite distance from the other. |
| In carrying a charge q from point A to point B, work done\[W=q\left( {{V}_{A}}-{{V}_{B}} \right)\]. This work may appear as change in KE/PE of the charge. The potential energy of two charges \[{{q}_{1}}\]and \[{{q}_{2}}\]at a distance r in air is\[\frac{{{q}_{1}}{{q}_{2}}}{4\pi {{\varepsilon }_{0}}r}\]. It is measured in joule. It may be positive, negative or zero depending on the signs of \[{{q}_{1}}\]and \[{{q}_{2}}\]. |
| Read the given passage carefully and give the answer of the following questions. |
A) \[k{{e}^{2}}\]
B) \[{{e}^{2}}/2\]
C) \[-k{{e}^{2}}/2\]
D) zero
Correct Answer: C
Solution :
(c) \[-k{{e}^{2}}/2\] \[W={{\left( P.E. \right)}_{final}}-{{\left( P.E. \right)}_{initial}}\] \[=\frac{k{{e}^{2}}}{2}-\frac{k{{e}^{2}}}{1}=\frac{-k{{e}^{2}}}{2}\]
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