A) \[3\times {{10}^{3}}V\]
B) \[6\times {{10}^{4}}V\]
C) \[-9\times {{10}^{3}}V\]
D) \[-3\times {{10}^{3}}V\]
Correct Answer: C
Solution :
(c) \[-9\times {{10}^{3}}V\] Here, \[q=2\mu C=2\times {{10}^{-6}}C,\,{{r}_{A}}=2\,m,\,{{r}_{B}}=1m\] \[\therefore \,\,\,{{V}_{A}}-{{V}_{B}}=\frac{q}{4\pi {{\varepsilon }_{0}}}\left[ \frac{1}{{{r}_{A}}}-\frac{1}{{{r}_{B}}} \right]\] \[=2\times {{10}^{-6}}\times 9\times {{10}^{9}}\left[ \frac{1}{2}-\frac{1}{1} \right]V\] \[=-9\times {{10}^{3}}V\]
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