A) \[17\times {{10}^{-22}}N/C\]
B) \[1.5\times {{10}^{-15}}N/C\]
C) \[1.9\times {{10}^{-10}}N/C\]
D) zero
Correct Answer: D
Solution :
(d) zero The electric field in region III is also zero. \[{{E}_{|||}}={{E}_{A}}-{{E}_{B}}=\frac{\sigma }{2{{\varepsilon }_{0}}}+\left( -\frac{\sigma }{2{{\varepsilon }_{0}}} \right)=0\]
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