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12th Class Physics Electrostatics & Capacitance Question Bank Case Based (MCQs) - Electrostatic Potential and Capacitance

  • question_answer
    A parallel plate capacitor has two square plates with equal and opposite charges. The surface charge densities on the plates are \[+\sigma \] and \[-\sigma \] respectively. In the region between the plates the magnitude of the electric field is:

    A) \[\frac{\sigma }{2{{\varepsilon }_{0}}}\]            

    B) \[\frac{\sigma }{{{\varepsilon }_{0}}}\]

    C) 0                                 

    D) None of these

    Correct Answer: B

    Solution :

    (b) \[\frac{\sigma }{{{\varepsilon }_{0}}}\] The magnitude of the electric field between the plate is \[E=\frac{\sigma }{2{{\varepsilon }_{0}}}-\left( -\frac{\sigma }{2{{\varepsilon }_{0}}} \right)=\frac{\sigma }{{{\varepsilon }_{0}}}\]


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