A) \[1.56\,\times {{10}^{-14}}J\]
B) \[5.5\times {{10}^{-14}}J\]
C) \[2.56\times {{10}^{-14}}J\]
D) \[4.56\times {{10}^{-14}}J\]
Correct Answer: C
Solution :
(c) \[2.56\times {{10}^{-14}}J\] \[U=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{r}_{2}}}{r}\] \[=\frac{9\times {{10}^{9}}\times 1.6\times {{10}^{-19}}\times 1.6\times {{10}^{-19}}}{9\times {{10}^{-15}}}=2.56\times {{10}^{-14}}J\]You need to login to perform this action.
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