12th Class Physics Electrostatics & Capacitance Question Bank Case Based (MCQs) - Electrostatic Potential and Capacitance

  • question_answer
    What is the potential difference across \[2\mu F\]capacitor in the circuit shown?

    A) 12 V    

    B)   4 V

    C) 6 V                              

    D) 18 V

    Correct Answer: C

    Solution :

    (c) 6 V \[{{E}_{net}}=16-6=10V\] \[{{C}_{eq}}=\frac{2\times 3}{2+2}=\frac{6}{5}\mu F\] Potential difference across \[2\mu C\] capacitor. \[{{V}_{1}}=\frac{Q}{{{C}_{1}}}=\frac{12\mu C}{2\mu F}=6V\]


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