12th Class Physics Electrostatics & Capacitance Question Bank Case Based (MCQs) - Electrostatic Potential and Capacitance

  • question_answer
    A capacitor with capacitance \[5\mu F\]is charged to \[5\mu C\]If the plates are pulled apart to reduce the capacitance to \[2\mu F\]how much work is done?

    A) \[6.25\times {{10}^{-6}}J\]      

    B) \[3.75\times {{10}^{-6}}J\]

    C) \[2.16\times {{10}^{-6}}J\]      

    D) \[2.55\times {{10}^{-6}}J\]

    Correct Answer: B

    Solution :

    (b) \[3.75\times {{10}^{-6}}J\] Work done =\[{{U}_{f}}-{{U}_{i}}\] \[=\frac{1}{2}\frac{{{q}^{2}}}{{{C}_{f}}}-\frac{1}{2}\frac{{{q}^{2}}}{{{C}_{i}}}\] \[=\frac{{{q}^{2}}}{2}\left[ \frac{1}{{{C}_{f}}}-\frac{1}{{{C}_{i}}} \right]\] \[=\frac{{{\left( 5\times {{10}^{-6}} \right)}^{2}}}{2}\left[ \frac{1}{2\times {{10}^{-6}}}-\frac{1}{5\times {{10}^{-6}}} \right]\] \[=3.75\times {{10}^{-6}}J\]


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