A) -1.1 J
B) 2 J
C) 2.5 J
D) 3 J
Correct Answer: A
Solution :
(a) -1.1 J \[U=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{r}\] \[=\frac{9\times {{10}^{9}}\times 4\times {{10}^{-6}}\times \left( -3 \right)\times {{10}^{-6}}}{0.1}=-1.1J\]
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