A) 36 m
B) 60 m
C) 72 m
D) 86 m
Correct Answer: C
Solution :
[c] As we know, braking distance, |
\[s=ut-\frac{1}{2}a{{t}^{2}}\] |
\[=30\times 4.8-\frac{1}{2}\times 6.25\times 4.8\times 4.8\] |
= 144 - 72 |
= 72 m |
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