A) \[\frac{253}{136}\]
B) \[\frac{357}{136}\]
C) \[\frac{479}{136}\]
D) \[1\]
Correct Answer: C
Solution :
From part (1) and (3), |
\[\cos R=\frac{8}{17}\] and \[\sin R=\frac{15}{17}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\tan R=\frac{\sin R}{\cos R}=\frac{15/17}{8/17}=\frac{15}{8}\] |
From part (3), \[\cos P=\frac{15}{17}\,\,\,\,\,\Rightarrow \,\,\,\,\,\sec P=\frac{17}{15}\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\tan R+\frac{3}{\sec P}-1=\frac{15}{8}+\frac{3}{(17/15)}-1\] |
\[=\frac{15}{8}+\frac{45}{17}-1=\frac{255+360-136}{136}=\frac{479}{136}\] |
So, option [c] is correct. |
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