A) \[\frac{\sqrt{29}}{5}\]
B) \[\frac{\sqrt{29}}{2}\]
C) \[\frac{2}{5}\]
D) \[\frac{5}{\sqrt{29}}\]
Correct Answer: A
Solution :
| In right \[\Delta PQR\] |
| \[{{(PR)}^{2}}={{(PQ)}^{2}}+{{(QR)}^{2}}\] |
| (By Pythagoras theorem) |
| \[={{(5)}^{2}}+{{(2)}^{2}}=25+4=29\,\,\,\Rightarrow \,\,\,PR=\sqrt{29}m\] |
| \[\therefore \] In right \[\Delta PQR\], |
| \[\cos ec\,\,R=\frac{\text{Hypotenuse}}{\text{Perpendicular}}=\frac{PR}{PQ}=\frac{\sqrt{29}}{5}\] |
| So, option [a] is correct. |
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