A) 0
B) 1
C) \[\frac{1}{\sqrt{2}}\]
D) \[\sqrt{2}\]
Correct Answer: D
Solution :
\[\sin A+\cos C=\frac{BD}{BA}+\frac{CD}{BC}\] |
\[=\frac{4}{4\sqrt{2}}+\frac{4}{4\sqrt{2}}\] |
\[=\frac{8}{4\sqrt{2}}=\frac{2}{\sqrt{2}}=\sqrt{2}\] |
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