A) \[\frac{7}{4}\]
B) \[\frac{4}{7}\]
C) \[\frac{\sqrt{65}}{4}\]
D) \[\frac{\sqrt{65}}{7}\]
Correct Answer: A
Solution :
In right \[\Delta TSP\] |
\[\cot y{}^\circ =\frac{Base}{Perpendicular}=\frac{PS}{TS}=\frac{7}{4}\] |
So, option [a] is correct. |
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