A) 86g
B) 53g
C) 50g
D) 36g
Correct Answer: B
Solution :
[b] Amount of water available = 100 - 20 = 80 g In 100 g, the amount of \[{{\operatorname{NH}}_{4}}CI\] at 353 K =66 g 80 g, the amount of \[{{\operatorname{NH}}_{4}}CI\] at 353 K = \[\frac{66}{100}\times 80\] = 52.8 g = 53 gYou need to login to perform this action.
You will be redirected in
3 sec