A) \[2.5\times {{10}^{3}}A{{m}^{-1}}\]
B) \[2.5\times {{10}^{5}}A{{m}^{-3}}\]
C) \[2.0\times {{10}^{3}}A{{m}^{-1}}\]
D) \[2.0\times {{10}^{5}}A{{m}^{-1}}\]
Correct Answer: B
Solution :
(b) \[2.5\times {{10}^{5}}A{{m}^{-3}}\] Here, \[n=500\text{ }turns/m\] \[l=1A.\text{ }{{\mu }_{r}}=500\] Magnetic intensity, \[H=nl=500{{m}^{-1}}\times 1A=500\,A{{m}^{-1}}\] As \[{{\mu }_{r}}=1+{{\chi }_{m}}\] or \[{{\chi }_{m}}=({{\mu }_{r}}-1)\] Magnetisation, \[M={{\chi }_{m}}H\] \[=\left( {{\mu }_{r}}-1 \right)H=(500-1)\times 500\,A{{m}^{-1}}\] \[=2.495\times {{10}^{5}}\,A{{m}^{-1}}\] \[\approx 2.5\times {{10}^{5}}A{{m}^{-1}}\]
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