A) \[25 m/{{s}^{2}}\]
B) \[0.25 m/{{s}^{2}}\]
C) \[2.5 m/{{s}^{2}}\]
D) \[1 m/{{s}^{2}}\]
Correct Answer: C
Solution :
| [c] \[\operatorname{Deceleration}=\frac{Change in velocity}{Time interval}\] .(i) |
| Given, change in velocity = 25 m/s |
| Time interval (for deceleration) = 10 s |
| Substituting above values in Eq. (i), we get |
| Deceleration \[=2.5{{m}^{2}}\] |
| Thus, deceleration of train A is 2.5 \[\operatorname{m}/{{s}^{2}}\]. |
You need to login to perform this action.
You will be redirected in
3 sec
