A) 6km/h
B) 12km/h
C) 20km/h
D) 36km/h
Correct Answer: D
Solution :
[d] Distance travelled between 10 : 40 AM to 11:00 AM. |
D = 40 - 28=12 km |
Time =20 min =\[\frac{20}{60}=\frac{1}{3}\operatorname{h}\] |
\[\therefore \] Speed between 10 : 40 AM to 11:00 AM |
\[=\frac{Distance\ travelled}{Time}\] |
= \[\frac{12}{\frac{1}{3}}\] = 36 km/h |
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