A) \[25 m/{{s}^{2}}\]
B) \[0.25 m/{{s}^{2}}\]
C) \[2.5 m/{{s}^{2}}\]
D) \[1 m/{{s}^{2}}\]
Correct Answer: C
Solution :
[c] \[\operatorname{Deceleration}=\frac{Change in velocity}{Time interval}\] .(i) |
Given, change in velocity = 25 m/s |
Time interval (for deceleration) = 10 s |
Substituting above values in Eq. (i), we get |
Deceleration \[=2.5{{m}^{2}}\] |
Thus, deceleration of train A is 2.5 \[\operatorname{m}/{{s}^{2}}\]. |
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