A) \[0\centerdot 053m\]
B) \[0\centerdot 136m\]
C) \[0\centerdot 157m\]
D) \[0\centerdot 236m\]
Correct Answer: C
Solution :
Here, \[\overrightarrow{B}=8\,.\,35\times {{10}^{-2}}\,\,\hat{i}\,T\] \[\overrightarrow{v}=2\times {{10}^{5}}\,\hat{i}+4\times {{10}^{5}}\hat{j}\,\,m/s\] \[m=1\,.\,67\times {{10}^{-27}}\,kg\] Pitch of the helix (i.e. the linear distance moved along the magnetic field in one rotation) is given by Pitch of the helix \[=\frac{2\pi m{{v}_{||}}}{qB}\] \[=\frac{2\times 3\,.\,14\times 1.\,67\times {{10}^{-27}}\times 2\times {{10}^{5}}}{1\,.\,6\,{{10}^{-19}}\times 8\,.\,33\times {{10}^{-2}}}=0.157\,m\]
You need to login to perform this action.
You will be redirected in
3 sec
