A) \[4\,m{{s}^{-2}}\]
B) \[-4\,m{{s}^{-2}}\]
C) \[-2\,m{{s}^{-2}}\]
D) \[2\,m{{s}^{-2}}\]
Correct Answer: B
Solution :
(b) \[-4\,m{{s}^{-2}}\] As \[F\bot B\] Hence, \[a\bot B\] \[\therefore \overrightarrow{a}\cdot \overrightarrow{B}=0\] \[\Rightarrow \,\,(x\,\widehat{i}\,+\,2\,\widehat{j})\cdot (2\,\widehat{i}\,+\,4\,\widehat{j})=0\] \[2x+8=0\Rightarrow x=-4\,m{{s}^{-2}}\]You need to login to perform this action.
You will be redirected in
3 sec