A) Bev
B) \[\frac{Be}{v}\]
C) \[\frac{B}{ev}\]
D) zero
Correct Answer: D
Solution :
(d) zero The force on electron \[F=qv\,B\,\sin \,\theta \] As the electron is moving parallel to B So, \[\theta =0{}^\circ \] \[\Rightarrow qvB\sin \theta =0\]You need to login to perform this action.
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