A) \[5x+3y=74\]
B) \[5x-3y=74\]
C) \[3x+5y=74\]
D) \[3x-5y=74\]
Correct Answer: C
Solution :
Cost of 6 tickets to Karol Bagh = 6x |
Cost of 10 tickets to Hauz Khas \[=10\,y\] |
Total cost = 148 |
Then, the situation can be represented algebraically as |
\[6x+10y=148\] |
\[3x\text{ }+\text{ }5y\text{ }=\text{ }74\] |
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