A) yes
B) no
C) do not say
D) None of these
Correct Answer: B
Solution :
| Given, equation of paths are |
| \[x-3y=2\] ...(1) |
| and \[-2x+6y=5\] ...(2) |
| Here, \[{{a}_{1}}=1,\,\,{{b}_{1}}=-3,\,\,{{c}_{1}}=-2\] |
| and \[{{a}_{2}}=-2,\,\,{{b}_{2}}=6,\,\,{{c}_{2}}=5\] |
| \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{-2},\] \[\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{-3}{6}=-\frac{1}{2}\] and \[\frac{{{c}_{1}}}{{{c}_{2}}}=\frac{-2}{-5}=\frac{2}{5}\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\] |
| So, the paths represented by the equations are parallel i.e., do not intersect each other. |
| So, option [b] is correct. |
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