A) \[\text{3x}+\text{2y}=8\]
B) \[3x-2y=8\]
C) \[6x+4y=16\]
D) \[15x-10y=45\]
Correct Answer: D
Solution :
For parallel lines, \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\] |
The equation given at [d], namely, \[15x-10y=45,\] as it satisfies the above relation. |
So, option [d] is correct. |
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