A) \[\frac{-b}{a}\]
B) \[\frac{c}{a}\]
C) \[\frac{b}{c}\]
D) \[-\frac{c}{a}\]
Correct Answer: B
Solution :
[b] Take \[x=1.\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,p(1)=a{{(1)}^{2}}+b(1)+c=a+b+c=0\] |
\[\therefore \] One zero \[(\alpha )=1\] |
Now, product of zeroes \[=\frac{c}{a}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1\cdot \beta =\frac{c}{a}\Rightarrow \beta =\frac{c}{a}\] |
\[\therefore \] Zeroes are 1 and \[\frac{c}{a}\]. |
So, option [b] is correct . |
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