A) intersects X-axis at two distinct points
B) touches X-axis at a point
C) neither touches nor intersects X-axis
D) either touches or intersects X-axis.
Correct Answer: C
Solution :
The graph of \[{{x}^{2}}+4=0\] |
The\[{{x}^{2}}\]is positive so the general shaph is U. Since the coefficient of x is zero so the graph is central about the Y-axis. The constant part of the equation is of value \[+4,\] so it lifts the vertex up from \[y=0\] to\[y=4\]. |
\[\therefore \] The graph of \[{{x}^{2}}+4=0,\] neither touches nor intersects X-axis. |
So, option [c] is correct. |
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