A) \[{{x}^{2}}-6x+2\]
B) \[{{x}^{2}}-36\]
C) \[{{x}^{2}}-6\]
D) \[{{x}^{2}}-3\]
Correct Answer: B
Solution :
Sum of zeroes \[(\alpha +\beta )=0\] |
One zero \[(\alpha )=6\] |
\[\therefore \,\,\,\,\,\,\beta =0-6=-6\] |
\[{{x}^{2}}-(\text{Sum of zeroes})x+\text{Product of zeroes }=\text{ }0\] \[{{x}^{2}}-0x+6\times (-6)=0\] |
\[{{x}^{2}}-36=0\] |
So, option [b] is correct. |
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