A) \[\frac{b}{a}\]
B) \[\frac{c}{a}\]
C) \[\frac{-c}{a}\]
D) \[\frac{-b}{a}\]
Correct Answer: C
Solution :
| [c]\[\frac{-c}{a}\] |
| Take \[x=-1\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,p(-1)=a{{(-1)}^{2}}+b(-1)+c=a-b+c=b-b=0\] \[[a+c=b]\] |
| \[\therefore \] one zero \[(\alpha )=1\] |
| \[\alpha \beta =\]product of zeroes \[=\frac{c}{a}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,(-1)\cdot \beta =\frac{c}{a}\Rightarrow \beta =-\frac{c}{a}\] |
| So, option [c] is correct. |
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