A) 1
B) 2
C) 0
D) 3
Correct Answer: C
Solution :
\[f(x)={{(x-2)}^{2}}+4\] |
\[={{x}^{2}}+4-4x+4\] |
\[={{x}^{2}}-4x+8\] |
\[D={{b}^{2}}-4ac\] |
\[={{(-4)}^{2}}-4\times 1\times 8=16-32=-16\] (1) |
\[D<0,\] so no real roots. |
So, option [c] is correct. |
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