10th Class Mathematics Polynomials Question Bank Case Based (MCQs) - Polynomials

  • question_answer
    The zeroes of the quadratic polynomial \[{{x}^{2}}+20x+96\]are:

    A) both positive

    B) both negative

    C) one positive and other negative

    D) both equal

    Correct Answer: B

    Solution :

    Let \[f(x)={{x}^{2}}+20x+96\]
    [\[96=12\times 8=6\times 16=2\times 48.....\]
    \[\therefore \]Here, we will take 12 and 8 as a factors of 96.
    So, middle term is \[20=12+8\]]
    For the zeroes of \[f(x),\]
                \[x+12=0\] or \[x+8=0\]
    \[\therefore \,\,\,\,x=-8,-12\]
    i.e., both zeroes are negative
    So, option [b] is correct.

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