A) \[2,-4\]
B) \[4,-2\]
C) \[2,-2\]
D) \[-4,-4\]
Correct Answer: B
Solution :
We have, |
\[f(x)={{x}^{2}}-2x-8={{x}^{2}}-4x+2x-8\] |
\[=x(x-4)+2(x-4)=(x-4)\,(x+2)\] |
For the zeroes of \[f(x),\] |
\[x-4=0\] or \[x+2=0\] |
\[\therefore \,\,\,\,\,\,\,\,\,x=4,-2\] |
[\[8=2\times 4=8\times 1\] |
\[\therefore \]We will take 2 and 4 as a factors of 8. |
So, middle term is \[-2=-4+2\]] |
So, option [b] is correct. |
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