A) \[k({{x}^{2}}-2x-8)\]
B) \[k({{x}^{2}}+2x-8)\]
C) \[k({{x}^{2}}+2x+8)\]
D) \[k({{x}^{2}}-2x+8)\]
Correct Answer: A
Solution :
| The graph cut x-axis in the above graph at points \[-2\] and 4 which are the zeroes of the graph. |
| Now, the required polynomial |
| \[=k[{{x}^{2}}-(\text{sum of zeroes})x+\text{product of zeroes}]\] |
| \[=k[{{x}^{2}}-(-2+4)x+(-2\times 4)]=k({{x}^{2}}-2x-8)\] |
| where, k is an arbitrary constant. |
| So, option [a] is correct. |
You need to login to perform this action.
You will be redirected in
3 sec
