A) \[\frac{1}{26}\]
B) \[\frac{1}{52}\]
C) \[\frac{3}{52}\]
D) \[\frac{3}{26}\]
Correct Answer: B
Solution :
| Total number of possible outcomes = 52 |
| There are 13 club cards, in which only 1 Jack. |
| Now, number of Jack in club, cards = 1 |
| \[\therefore \] Favourable outcomes = 1 |
| \[\therefore \] P (getting a jack of clubs) |
| \[=\frac{\text{Favourable outcomes}}{\text{Possible outcomes}}=\frac{1}{52}\] |
| So, option [b] is correct. |
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