A) 0
B) 1
C) \[\frac{1}{2}\]
D) \[\frac{1}{4}\]
Correct Answer: C
Solution :
| Let E be the event of getting at least two heads. |
| \[\therefore \,\,\,\,\,\,\,\,E=\{HHT,HTH,THH,HHH\}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,n(E)=4\] |
| \[\therefore \] Required probability \[=\frac{n(E)}{n(S)}=\frac{4}{8}=\frac{1}{2}\] |
| So, Option [c] is correct. |
You need to login to perform this action.
You will be redirected in
3 sec