A) \[\frac{1}{5}\]
B) \[\frac{2}{5}\]
C) \[\frac{3}{5}\]
D) \[\frac{4}{5}\]
Correct Answer: D
Solution :
| [d] Number of red balls =5. |
| \[\therefore \] Probability of drawing a red ball \[=\frac{5}{25}=\frac{1}{5}.\] |
| As \[P(E)+P(\bar{E})=1.\] |
| \[\therefore \] Probability of not drawing a red ball |
| \[=1-\frac{4}{5}=\frac{4}{5}.\] |
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