A) terminating
B) recurring
C) non-terminating and non-recurring
D) None of the above
Correct Answer: A
Solution :
\[\frac{686}{{{2}^{2}}\times {{5}^{7}}\times {{7}^{3}}}=\frac{2\times {{7}^{3}}}{{{2}^{2}}\times {{5}^{7}}\times {{7}^{3}}}=\frac{2}{{{2}^{2}}\times {{5}^{7}}}\] denominator is in the form of \[{{2}^{n}}{{5}^{m}}\]so terminating.
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